y^2+2y=2y-5

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Solution for y^2+2y=2y-5 equation: 



y^2+2y=2y-5

We move all terms to the left:

y^2+2y-(2y-5)=0

We get rid of parentheses

y^2+2y-2y+5=0

We add all the numbers together, and all the variables

y^2+5=0

a = 1; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·1·5
Δ = -20
Delta is less than zero, so there is no solution for the equation

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